[백준 12813] 이진수 연산

 

차례대로 A AND B, A OR B, A XOR B, NOT A, NOT B 를 출력하면 된다.

 

public class Main {
    
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        
        char a[] = sc.next().toCharArray();
        char b[] = sc.next().toCharArray();
        
        for(int i=0; i<a.length; i++) {
            if(a[i] == '1' && b[i] == '1')
                System.out.print(1);
            else System.out.print(0);
        }
        System.out.println();
        
        for(int i=0; i<a.length; i++) {
            if(a[i] == '1' || b[i] == '1')
                System.out.print(1);
            else System.out.print(0);
        }
        System.out.println();
        
        for(int i=0; i<a.length; i++) {
            if(a[i] != b[i])
                System.out.print(1);
            else System.out.print(0);
        }
        System.out.println();
        
        for(int i=0; i<a.length; i++) {
            if(a[i] == '0')
                System.out.print(1);
            else System.out.print(0);
        }
        System.out.println();
        
        for(int i=0; i<b.length; i++) {
            if(b[i] == '0')
                System.out.print(1);
            else System.out.print(0);
        }
    }
}